The correct option is C 100 J
From 1st equation of motion we have, v2=u2+2gh
As it is dropped so, u=0 and g=10 m/s2 and h=5 m
Putting these values we get, v=10 m/s2
So, the body would attain the maximum kinetic energy when it strikes the ground, i.e. K.E = 12×m×v2=12×2×102=100 J
Alternate way:
According to the law of conservation of energy, during free fall, the potential energy of the body at maximum height will be equal to the maximum K.E of the body just before hitting the ground. i.e. maximum potential energy = maximum kinetic energy.
So, maximum potential energy =mgh=2×10×5 =100 J which is equal to kinetic energy.