A body of mass 2kg is kept on a rough horizontal surface. It is subjected to a force of a) 5 N b) 20 N.
Given μs=0.5 and μk=0.4. Taking g=10m/s2, find the acceleration in each case.
A
zero, zero
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B
zero, 5m/s2
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C
zero, 6m/s2
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D
4m/s2,6m/s2,
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Solution
The correct option is C zero, 6m/s2 N=2g=20N, Hence fs=μsN=10N
since applied force Fa=5 N in case (a) is 5N<10N, the body will be at rest
Fb=20 N in case (b) fk=μkN=8N: since Fb>fk in the second case, the body will acceletate.
Hence 20−8=2a⇒a=6m/s2