wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass 2 kg is moving uniformly with the velocity of (2^i+3^j+4^k) m/s. Find its kinetic energy.

A
21 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
25 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
37 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
29 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 29 J
Given mass (m)=2 kg and velocity,
v =2^i+3^j+4^k m/s

We know that,
Kinetic energy =12mv.v=12m(|v|)2
The magnitude of velocity will be,

|v|=22+33+42=29 m/s

Hence, kinetic energy will be,

=12×2×(29)2

=29 J

Hence option D is the correct answer

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon