The correct option is D 29 J
Given mass (m)=2 kg and velocity,
→v =2^i+3^j+4^k m/s
We know that,
Kinetic energy =12m→v.→v=12m(−→|v|)2
The magnitude of velocity will be,
|→v|=√22+33+42=√29 m/s
Hence, kinetic energy will be,
=12×2×(√29)2
=29 J
Hence option D is the correct answer