wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass 20g connected to a spring of spring constant k, executes simple harmonic motion with a frequency of (5π)Hz. The value of spring constant is

A
4Nm1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3Nm1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2Nm1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5Nm1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2Nm1
Here, m=20g=20×103kg,v=5πHz
v=12πkm
k=4π2v2m=4π2[5π]2×20×103=2Nm1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Aftermath of SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon