A body of mass 20 kg is kept initially at rest. A force of 80 N is applied on the body then the acceleration produced in the body is $3 m / s^{2}$ , force of friction acting on the body is:

80 N

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12 N

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20 N

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Solution

The correct option is B 20 N
Given : $F = 80$ N $m = 20$ kg $a = 3$ $m / s^{2}$
Let the frictional force acting in the opposite direction be $f$ .
$∴$ $m a = F - f$
$⟹$ $f = F - m a = 80 - 20 \times 3 = 20$ N

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A body of mass 20 kg is kept initially at rest. A force of 80 N is applied on the body then the acceleration produced in the body is 3m/s2, force of friction acting on the body is:

The correct option is B 20 NGiven : F=80 N m=20 kg a=3 m/s2Let the frictional force acting in the opposite direction be f.∴ ma=F−f⟹ f=F−ma=80−20×3=20 N

A body of mass 20 kg is kept initially at rest. A force of 80 N is applied on the body then the acceleration produced in the body is $3 m / s^{2}$ , force of friction acting on the body is:

The correct option is B 20 N
Given : $F = 80$ N $m = 20$ kg $a = 3$ $m / s^{2}$
Let the frictional force acting in the opposite direction be $f$ .
$∴$ $m a = F - f$
$⟹$ $f = F - m a = 80 - 20 \times 3 = 20$ N