A body of mass $20 k g$ moves with an acceleration of $2 m / s^{2}$ . The rate of change of momentum in SI unit is:

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Solution

The correct option is D 40
Given:
Mass of the body, $m = 20 k g$
Acceleration, $a = 2 m / s^{2}$

Using Newton's second law of motion, force equals rate of change of momentum.
$F = \frac{Δ p}{Δ t}$

For a body of constant mass,
$F = m a$

So, rate of change of momentum is:
$\frac{Δ p}{Δ t} = m a$
$\frac{Δ p}{Δ t} = 20 k g \times 2 m / s^{2}$
$\frac{Δ p}{Δ t} = 40 N$

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