A body of mass $20 k g$ is moving with a velocity of $1 \frac{m}{s}$ Another body B of mass $1 k g$ is moving wills a velocity of $20 \frac{m}{s}$ . Find the ratio of kinetic energy of A and B

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Solution

Step 1: Given data:
For body A:
Mass $= 20 k g$
Velocity $= 1 \frac{m}{s}$
For body B:
Mass $= 1 k g$
Velocity $= 20 \frac{m}{s}$
Formula used: $k i n e t i c e n e r g y = \frac{1}{2} \times m a s s \times {(v e l o c i t y)}^{2}$
Step 2: Calculate the kinetic energy,
To find Kinetic Energy of A:
$K . E ._{A} = \frac{1}{2} \times 20 \times 1^{2}$
$K . E ._{A} = 10 J$
To find Kinetic Energy of B:
$K . E ._{B} = \frac{1}{2} \times 1 \times 20^{2}$
$K . E ._{B} = 200 J$
Step 3: To find ratio of kinetic energy of A and B:
$\frac{{K . E .}_{A}}{{K . E .}_{B}} = \frac{10}{200} = \frac{1}{20}$
${K . E .}_{A} : {K . E .}_{B} = 1 : 20$
Thus, the ratio of the kinetic energy of A and B is $1 : 20$

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A body of mass 20kg is moving with a velocity of 1ms Another body B of mass 1kg is moving wills a velocity of 20ms. Find the ratio of kinetic energy of A and B

A body of mass $20 k g$ is moving with a velocity of $1 \frac{m}{s}$ Another body B of mass $1 k g$ is moving wills a velocity of $20 \frac{m}{s}$ . Find the ratio of kinetic energy of A and B