Question

A body of mass $2kg$ slides down a curved track which is quadrant of a circle of radius $1m$ as shown in figure. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

• A. $2m{s}^{-1}$
• B. $0.5m{s}^{-1}$
• C. $19.6m{s}^{-1}$
• D. $4.43m{s}^{-1}$

Answer 1

The correct option is D $4.43m{s}^{-1}$

By conservation of energy, $mgh=\frac{1}{2}m{v}^2$
$\Rightarrow v=\sqrt{2gh}=\sqrt{2\times 9.8\times 1}=\sqrt{19.6}=4.43m{s}^{-1}$