A body of mass 2 kg moving with a velocity of 3 m/sec collides head on with a body of mass 1 kg moving in opposite direction with a velocity of 4 m/sec. After collision, two bodies stick together and move with a common velocity which in m/sec is equal to

Q. A body of mass

3 k g

moving with a velocity

(2^i + 3^j + 3^k) m / s

collides with another body of mass

4 k g

moving with a velocity

(3^i + 2^j - 3^k) m / s

. The two bodies stick together after collision. The velocity of the composite body is

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A body of mass 3 kg moving with a velocity of 4 m/s towards left collides head on with a body of mass 4 kg moving in opposite direction with a velocity of 3 m/s. After collision the two bodies stick together and move with a common velocity which is :

The correct option is A zeroGiven : m1=3kg m2=4kg u1=4 m/s u2=3 m/sLet common velocity of the body be VApplying conservation of momentum :m1u1−m2u2=(m1+m2)V3×4−4×3=(3+4)V ⟹V=0 m/s

The correct option is A zero
Given : $m_{1} = 3 k g$ $m_{2} = 4 k g$ $u_{1} = 4$ $m / s$ $u_{2} = 3$ $m / s$
Let common velocity of the body be $V$
Applying conservation of momentum :
$m_{1} u_{1} - m_{2} u_{2} = (m_{1} + m_{2}) V$

$3 \times 4 - 4 \times 3 = (3 + 4) V$ $⟹ V = 0$ $m / s$