Question

A body of mass 300 g kept at rest breaks into two parts due to internal forces. One part of mass 200 g is found to move at a velocity of $12m{s}^{-}1$towards the east.

The velocity of the other part will be?

$east\Rightarrow +ve;west\Rightarrow -ve$

• A. $24m{s}^{-}1$ towards west
• B. $14m{s}^{-}1$ towards east
• C. $24m{s}^{-}1$ towards east
• D. $54m{s}^{-}1$ towards south

Answer 1

The correct option is (A) 24 m/s towards west

Step 1, Given data

Mass of the body = 300 g = 0.3 kg

Mass of the broken part = 200 g = 0.2 kg

Velocity of the broken part = 12 m/s

Step 2, Finding the velocity of the second part

We know,

According to the law of conservation of linear momentum,

Initial momentum = Final momentum

$0.3\times 0=0.2\times 12-0.1\times v$

After solving

v = 24 m/s

Hence, the Velocity of the other broken part is 24 m/s