Question

A body of mass $300kg$ is moved through $10m$ along a smooth inclined plane of an angle ${30}^{\circ }$. The work done in moving the mass in joules is:
($g=9.8{ms}^{-2}$)

• A. $9800$
• B. $14700$
• C. $3450$
• D. $4900$

Answer 1

The correct option is B $14700$

Work done in moving the body up the inclined plane is equal to the gain in potential energy of the body.

Thus work done$=mgh=mgdsin\theta$

$=300\times 9.8\times 10\times sin{30}^{\circ }$

$=14700J$