A body of mass 4 gm carrying a charge 1 $μ$ C starts from rest at the positive plate and reaches the negative plate of a parallel plate condenser with final velocity of 0.3 m/s. The potential difference between the plates is?

180 V

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360 V

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90 V

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18 V

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Solution

The correct option is A 180 V
$\frac{1}{2} m v^{2} = q V$
$\frac{1}{2} \times 4 \times 10^{- 3} \times 9 \times 10^{- 2} = 10^{- 6} V$
$V = 180 V$

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A body of mass 4 gm carrying a charge 1μ C starts from rest at the positive plate and reaches the negative plate of a parallel plate condenser with final velocity of 0.3 m/s. The potential difference between the plates is?

The correct option is A 180 V12mv2=qV 12×4×10−3×9×10−2=10−6V V=180 V

A body of mass 4 gm carrying a charge 1 $μ$ C starts from rest at the positive plate and reaches the negative plate of a parallel plate condenser with final velocity of 0.3 m/s. The potential difference between the plates is?

The correct option is A 180 V
$\frac{1}{2} m v^{2} = q V$
$\frac{1}{2} \times 4 \times 10^{- 3} \times 9 \times 10^{- 2} = 10^{- 6} V$
$V = 180 V$