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Relative Position

A body of mas...

Question

A body of mass $4 k g$ is acted on by a force which varies as shown in figure. The momentum acquired is:

A

280 N - s

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B

140 N - s

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C

70 N - s

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D

210 N - s

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Solution

The correct option is C $70 N - s$
The area under force verses time graph gives us the impulse of the object and impulse = change in momentum
Total area under the graph $= \frac{1}{2} (b a s e \times a l t i t u d e) + l e n g t h \times b r e a d t h = 20 + 50 = 70$

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