Question

A body of mass $40$ gm is moving with a constant velocity of $2$ cm/sec on a horizontal frictionless table. The force on the table is-

Answer 1

$m=40g,4\times {10}^{-2}kg,v=2cm/s=2\times {10}^{-2}m/s$

$N=mg$

$\left({4\times 10}^{-2}\right)9.8N$

$39.2\times {10}^{-2}N$

$0.392N$