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Standard XIII

Physics

Perfectly Inelastic Collision

A body of mas...

Question

A body of mass 40 kg having velocity 4 m/s collides with another body of mass 60 kg having velocity 2 m/s. If the collision is inelastic, then loss in kinetic energy will be

440 J

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392 J

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48 J

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144 J

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Solution

The correct option is C
48 J

Loss in kinetic energy $= \frac{1}{2} \frac{m_{1} m_{2} (u_{2} - u_{2})^{2}}{m_{1} + m_{2}} = \frac{1}{2} (\frac{40 \times 60}{40 + 60}) (4 - 2)^{2} = 48 J$

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A body of mass 40 kg having velocity 4 m/s collides with another body of mass 60 kg having velocity 2 m/s. If the collision is inelastic, then loss in kinetic energy will be

The correct option is C 48 J Loss in kinetic energy =12m1m2(u2−u2)2m1+m2=12(40×6040+60)(4−2)2=48 J

The correct option is C
48 J

Loss in kinetic energy $= \frac{1}{2} \frac{m_{1} m_{2} (u_{2} - u_{2})^{2}}{m_{1} + m_{2}} = \frac{1}{2} (\frac{40 \times 60}{40 + 60}) (4 - 2)^{2} = 48 J$