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Byju's Answer
Standard IX
Physics
Power
A body of mas...
Question
A body of mass
40
kg is dragged
8
meter on a rough horizontal surface in
10
with a constant velocity by a constant force of
20
N, then calculate the work done by the force and total work done by all the forces.
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Solution
M
=
40
k
g
F
=
20
N
t
=
10
s
Friction force
=
μ
m
g
=
0.2
∗
40
∗
10
=
80
N
Net force in forward direction
=
20
−
80
=
60
N
So acceleration
=
a
=
F
o
r
c
e
/
m
=
60
/
2
=
30
m
/
s
²
Initial speed
=
u
=
0
Distance traveled
=
s
=
u
t
+
1
/
2
a
t
²
=
0
+
1
/
2
∗
30
∗
10
²
=
0.000166
m
Work done by
F
=
F
∗
s
=
20
∗
0.00016
=
0.0032
k
J
Work done by Friction force
=
−
30
∗
0.0032
=
−
0.096
k
J
(heat dissipated)
The kinetic energy of the body
=
1
/
2
m
v
²
=
1
/
2
m
(
2
a
s
)
=
2
∗
30
∗
0.00016
=
0.0096
k
J
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