Question

A body of mass 400 g slides on a rough horizontal surface. If the frictional force is 3.0 N. Find the angle made by the contact force on the body with the vertical.

• A. ${37}^0$
• B. ${53}^0$
• C. ${63}^0$
• D. ${27}^0$

Answer 1

The correct option is A ${37}^0$

Given,

$m=400g=0.4kg$

$f_{\mu }=3.0N$

Take, $g=10m/s^2$

From the free body diagram,

$tan\theta =\frac{f_{\mu }}{N}=\frac{f_{\mu }}{mg}$

$tan\theta =\frac{3}{0.4\times 10}$

$tan\theta =0.75$

$\theta =ta{n}^{-1}\left(0.75\right)$

$\theta ={37}^0$

The correct option is A.