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Question

A body of mass 4m at rest explodes into three pieces. Two of the pieces each of mass m move with a speed v each in mutually perpendicular directions. The total energy released is:

A
12mv2
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B
mv2
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C
32mv2
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D
52mv2
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Solution

The correct option is B 32mv2
By momentum conservation
2mv'=2mv2mv'=2mV
v'=v2v'=v2
KE=2l2KE=2l2mv2+12mv2+12(2m)v22(2m)v22
=mv2+mv22=mv2+mv22
=32mv2

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