A body of mass $5 g m$ is executing S.H.M. about a point with amplitude $10 c m$ . Its maximum velocity is $100 c m / s$ . Then, the velocity of body will be $50 c m / s$ at a distance of (in $c m$ )

\sqrt{2}

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\sqrt{3}

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\sqrt{2}

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Solution

The correct option is B 5 $\sqrt{3}$
Given $v_{m a x} = 100 c m / s v_{m a x} = a ω \Rightarrow ω = \frac{100}{10} = 10 r a d / s e c v = ω \sqrt{a^{2} - y^{2}} \Rightarrow 50 = 10 \sqrt{10^{2} - y^{2}} \Rightarrow y = 5 \sqrt{3} c m$

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A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm. Its maximum velocity is 100 cm/sec. Its velocity will be 50 cm/sec at a distance

[CPMT 1976]

Q. A body of mass

5 g r a m

is executing S.H.M. about a fixed point

O

. With an amplitude of

10 c m

, its maximum velocity is

100 c m / s

. Its velocity will be

50 c m / s

at a distance (in

c m

A body of mass $5 g m$ is executing S.H.M. about a point with amplitude $10 c m$ . Its maximum velocity is $100 c m / s$ . Then, the velocity of body will be $50 c m / s$ at a distance of (in $c m$ )

Q. A body of mass 1 gram executes a linear S.H.M. of period 1.57 s. If its maximum velocity is 0.8 m/s, then its maximum displacement from the mean position is

Q. A body executing S.H.M has a maximum acceleration equal to

48

/ {sec}^{2}

and maximum velocity equal to

12

sec

. The amplitude of S.H.M is?

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A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm. Its maximum velocity is 100 cm/s. Then, the velocity of body will be 50 cm/s at a distance of (in cm)

The correct option is B 5√3Given vmax=100 cm/svmax=aω⇒ω=10010=10 rad/secv=ω√a2−y2⇒50=10√102−y2⇒y=5√3 cm

A body of mass $5 g m$ is executing S.H.M. about a point with amplitude $10 c m$ . Its maximum velocity is $100 c m / s$ . Then, the velocity of body will be $50 c m / s$ at a distance of (in $c m$ )

The correct option is B 5 $\sqrt{3}$
Given $v_{m a x} = 100 c m / s v_{m a x} = a ω \Rightarrow ω = \frac{100}{10} = 10 r a d / s e c v = ω \sqrt{a^{2} - y^{2}} \Rightarrow 50 = 10 \sqrt{10^{2} - y^{2}} \Rightarrow y = 5 \sqrt{3} c m$