Question

A body of mass $5gm$ is executing S.H.M. about a point with amplitude $10cm$. Its maximum velocity is $100cm/s$. Then, the velocity of body will be $50cm/s$ at a distance of (in $cm$)

• A. 10$\sqrt{2}$
• B. 5$\sqrt{3}$
• C. 5$\sqrt{2}$
• D. 5

Answer 1

The correct option is B 5$\sqrt{3}$

Given $v_{max}=100cm/s{v}_{max}=a\omega \Rightarrow \omega =\frac{100}{10}=10rad/secv=\omega \sqrt{a^2-y^2}\Rightarrow 50=10\sqrt{{10}^2-y^2}\Rightarrow y=5\sqrt{3}cm$