A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.
Given: The mass of the body is 5 kg and the two perpendicular forces are 8 N and 6 N .
The forces on the body are shown below:
The resultant force is given as,
F R = 8 2 + 6 2 = 64 + 36 = 10 N
The tangent of the angle is given as,
tan θ = 6 8 θ = tan − 1 ( 3 4 ) = 37 °
Newton’s second law of the motion is given as,
F = m a
By substituting the given values in the above expression, we get
10 N = ( 5 kg ) a a = 2 m / s 2
Thus, the magnitude of acceleration is 2 m / s 2 and its direction is along the direction of the resultant force. The direction of resultant force is at an angle of 37 ° with 8 N force.
Given: The mass of the body is
The forces on the body are shown below:
The resultant force is given as,
The tangent of the angle is given as,
Newton’s second law of the motion is given as,
By substituting the given values in the above expression, we get
Thus, the magnitude of acceleration is
