Question

A body of mass $5kg$ is acted upon by two perpendicular forces $8N$ and $6N$.Give the magnitude and direction of the acceleration of the body.

Answer 1

Mass of the body, $m=5kg$
The given situation can be represented as follows:
The resultant of two forces is given as (in figure) is the angle made by $R$ with the force of 8 N= tan${}^{-1}$(-6/8) = -36.870

The negative sign indicates that angle is in the clockwise direction with respect to the force of magnitude $8N$.

As per Newton's second law of motion, the acceleration ($a$) of the body is given as:

$F=ma$

$a=F/m=10/5=2m$

Mass of the body, $m=5kg$
The given situation can be represented as follows:
The resultant of two forces is given as in the figure.

The angle made by $R$ with the force of $8N$
$={tan}^{-1}(-6/8)=-36.870$

The negative sign indicates that angle is in the clockwise direction with respect to the force of magnitude 8 N.

As per Newtons second law of motion, the acceleration ($a$) of the body is given as:

$F=ma$

$a=F/m=10/5=2m$$/s^2$