Question

A body of mass $5kg$ is moved up over $10m$ along a smooth inclined plane of inclination of ${30}^0$ with the horizontal. If $g=10m/s^2$, the work done by the force will be:

• A. $500J$
• B. $2500J$
• C. $250J$
• D. $25J$

Answer 1

Answer: (C)

$250J$

The displacement against the gravitational force is $S\sin \theta$
or
$10\sin {30}^o=5m$

Thus we get the work done as gravitational force x displacement (in vertical direction)

$5g\times 5=250J$