CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Center of Mass as an Average Point

A body of mas...

Question

A body of mass 5 kg is moving with a uniform velocity of 10m/s. It is acted upon by a force of 20N. What will be its velocity after 1 sec?

Open in App

Solution

$M = 5 k g$
a= $\frac{v - u}{t}$
$\frac{V - 10}{1}$
$f = 20 N$
$f = m \times a$
$20 N = 5 k g \times (V - 10)$
$4 = (v - 10)$
$v = 14$

Suggest Corrections

thumbs-up

1

Similar questions

Q. A body of mass

10 k g

is acted upon by a force given by equation

F = (3 t^{2} - 30)

Newtons. the initial velocity of the body is

10 m / s

. The velocity of the body after

5 s e c s

Q. A car of mass 1000 kg is moving with velocity of

10 m / s

and is acted upon by a forward force of 1000 N due to engine and retarding force of 500 N. The velocity after 10 seconds will be:

Q. A body of mass 5

k g

is moving with a velocity 20

m / s .

If a force of 100

N

is applied to it for 10 s in the same direction as its velocity, what will be the velocity of the body?

Q. A body of mass

10 kg

is moving with a constant velocity

10 m/s

. When a constant force acts for

4 s

on it, it moves with a velocity

2 m/s

in the opposite direction. The magnitude of force acting on the body is

Q. A body of mass J kg is moving with velocity of 10

m s^{- 1}

.After force is applied to it so that in 25 sec it attains a velocity of 35 m

s^{- 1}

. Calculate the value of force applied.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Just an Average Point?

PHYSICS

Watch in App

explore_more_icon

Explore more

Center of Mass as an Average Point

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon