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Intuition for COM

A body of mas...

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A body of mass 5 kg is pulled by a force \overrightarrow F=(-4^ i + 3^ j )N from rest on a smooth horizontal table in x z plane. the time at which it will attain a speed of 4m/s i

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\to F = (40^i + 10^j) N

acts on a body of mass

5 kg

. If the body starts from rest, its position vector

\to r

t = 10 s

Q. A body of mass

5 kg

under the action of constant force

\to F = F_{x}^i + F_{y}^j

has velocity at

t = 0 s

\to u = (6^i - 2^j) m/s

t = 10 s

\to v = 6^j m/s

F

Q. A body with mass 5 kg is acted upon by a force F = ( -3

^i

^j

)N. If its initial velocity at t=0 is v = ( 6

^i

^j

s^{- 1}

, the time at which it will just have a velocity along the y-axis is

(3^i + 4^j) N

acts on a body and displaces it by

(3^i + 4^j)

meters. The work done by the force is
(Given that formula for work done is

W = \to F . \to s)

Q. Following forces start acting on a particle at rest at the origin of the co-ordinate system simulaneously

_{1} = - 4^i - 5^j + 5^k

_{2} = 5^i + 8^j + 6^k

_{3} = - 3^i + 4^j - 7^k

_{4} = 2^i - 3^j - 2^k

then the particle will move

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