You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

F=ma

A body of mas...

Question

A body of mass $5 k g$ moving on a horizontal surface with a velocity of $10 m s^{- 1}$ comes to rest in $2 s$ . The force required to make this body move with a velocity of $10 m s^{- 1}$ on the same surface is:

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $25 N$
$0 = 10 + a t = 10 + 2 a$
$a = - 5 m / s^{2}$
$F = m a = 5 \times 5 = 25 N$

Suggest Corrections

Similar questions

Q. A body of mass

2 k g

moving on a horizontal surface with an initial velocity of

4 m / s

comes to rest after

2 s

. If one wants to keep this body moving on the same surface with a velocity of

4 m / s

, the force required is:

Q. A body of mass

2 k g

moving on a horizontal surface with an initial velocity of

4 m s^{- 1}

, comes to rest after

2 s

. If one wants to keep this body moving on the same surface with a velocity of

4 m s^{- 1}

, the force required is:

A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m/sec, the force required is

Q. A body of mass

2 k g

moving on horizontal surface with an initial velocity of

4 m / s e c

comes to rest after

2 s e c

. If one wants to keep this body moving on the same surface with a velocity of

4 m / s e c

, then the force required is:-

Q. A body of mass

5 k g

is moving with a constant velocity of

18

m / s

on a friction less horizontal surface. The force required to keep this body moving with the same velocity is

Join BYJU'S Learning Program

A body of mass 5 kg moving on a horizontal surface with a velocity of 10 ms−1 comes to rest in 2s. The force required to make this body move with a velocity of 10 ms−1 on the same surface is:

The correct option is C 25 N0=10+at=10+2aa=−5m/s2F=ma=5×5=25N

A body of mass $5 k g$ moving on a horizontal surface with a velocity of $10 m s^{- 1}$ comes to rest in $2 s$ . The force required to make this body move with a velocity of $10 m s^{- 1}$ on the same surface is:

The correct option is C $25 N$
$0 = 10 + a t = 10 + 2 a$
$a = - 5 m / s^{2}$
$F = m a = 5 \times 5 = 25 N$