A body of mass 5 kg rests on a rough horizontal surface of coefficient of friction 0.2. The body is pulled through a distance of 10 m by a horizontal force of 25 N. The kinetic energy acquired by it is :
A
200 J
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B
150 J
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C
100 J
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D
50 J
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Solution
The correct option is B 150 J Normal Reaction on the body=N=mg=5×10=50N
Horizontal force acting on the bodyFH=25N
Frictional force acting on the body Ff=μN=0.2×50=10N
Net force acting on the body Fnet=FH−Ff=25−10=15N
By work-energy theorem,
KE acquired by the body= Work done on the body=Fnet.s=15×10=150J