CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
594
You visited us 594 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass 5 kg rests on a rough horizontal surface of coefficient of friction 0.2. The body is pulled through a distance of 10 m by a horizontal force of 25 N. The kinetic energy acquired by it is :

A
200 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
150 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
100 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
50 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 150 J
Normal Reaction on the body=N=mg=5×10=50N
Horizontal force acting on the bodyFH=25N
Frictional force acting on the body Ff=μN=0.2×50=10N
Net force acting on the body Fnet=FHFf=2510=15N
By work-energy theorem,
KE acquired by the body= Work done on the body=Fnet.s=15×10=150J

Hence, correct answer is option B

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon