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Question

A body of mass 5 kg is dropped from a tower of height 10 m. Find the difference between work done (J) by gravity and change in potential energy of the body from A to B (Take g=10ms2)


A
1000 joule
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B
100 joule
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C
1000 joule
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D
2000 joule
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Solution

The correct option is C 1000 joule

Work done by gravity from 'A' to 'B'
WAB=+mgh;
because gravity is acting downwards and body is also getting displaced downwards.

Now change in potential energy from 'A' to 'B'
ΔUAB=UBUA ...(i)=mghBmghA=mg(0)mgh=mgh
(Where B is the refrence point)

Now, difference between workdone (J) by gravity and change in potential energy of body from A to B is given by
WABUAB=(+mgh(mgh))=2mgh=2×5×10×10=1000 joule

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