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Question

A body of mass 5 kg is moving along a straight line with a velocity of 2 ms1. A variable force F started acting on it for a time period of 0.5 s as shown in force - time curve. The final velocity of the block is


A
2 ms1
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B
2.2 ms1
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C
2.5 ms1
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D
2.7 ms1
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Solution

The correct option is C 2.5 ms1

Impulse = Area under F - t curve
=A1A2=12(0.4+0.2)×105×0.1
=30.5=2.5 N -s
m(vu)=2.5
5(v2)=2.5,v=2.5 ms1
(c)
Why this question?

"Application of graph: Impulse is given by area under the F-t curve ."
Caution : A2 is negative as force retards the motion


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