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Question

A body of mass 5 kg starts from rest and moves in a straight line under the influence of two variable forces F1=(10t+6t) N and F2=(15−6t) N, acting in same direction. Find the power delivered by force F1 at t=2 sec.

A
130 J/s
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B
230 J/s
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C
30 J/s
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D
350 J/s
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Solution

The correct option is B 230 J/sTotal force F=F1+F2 F=(10t+6t)+(15−6t) F=10t+15 ⟹ma=10t=15 ⟹5a=10t+15 ⟹a=2t+3 ⟹dvdt=2t+3 Integrating both sides: ∫v0dv=∫20(2t+3)dt ⟹v=(t2+3t)|20 ⟹v=2×2+3×2=10 m/s Work done by force F1 =F1.v=F1vcosθ Here θ=0∘ ∴ Work done by force F1 at t=2 s =(10×2+62)×10=230 J/s

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