A body of mass $50 k g$ has a volume of $0.049 m^{3}$ . The buoyant force on it when it is completely immersed inside the water would be

50 k g f

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50 N

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49 N

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49 k g f

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Solution

The correct option is D $49 k g f$
buoyant force = density of water $\times$ volume inside water
= 1000 $k g / m^{3} \times 0.049 m^{3}$
Buoyant fore = 49 kgf.

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A body of mass 50kg has a volume of 0.049m3. The buoyant force on it when it is completely immersed inside the water would be

The correct option is D 49kgfbuoyant force = density of water × volume inside water = 1000 kg/m3×0.049m3Buoyant fore = 49 kgf.

A body of mass $50 k g$ has a volume of $0.049 m^{3}$ . The buoyant force on it when it is completely immersed inside the water would be

The correct option is D $49 k g f$
buoyant force = density of water $\times$ volume inside water
= 1000 $k g / m^{3} \times 0.049 m^{3}$
Buoyant fore = 49 kgf.