Question

A body of mass 500 g is at rest on a friction less surface. Calculate the distance travel by 10 seconds when acted upon by a force?

Answer 1

We have,

$m=500g,t=10s,f=fN$

Since,$f=ma$

So, $a=\frac{f}{m}=\frac{f}{500}m{s}^2$

Now, By using:

$s=ut+\frac{1}{2}a{t}^2$

$=0+0.5\times \frac{f}{500}\times 100$ Since $u=0$

$=0.1f$m