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Question

A body of mass 500 g which is initially at rest is acted upon by a force. The body moves a distance of 4 m in 2 s. The force applied is _____.

A
1 N
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B
2 N
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C
3 N
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D
4 N
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Solution

The correct option is A 1 N
Given,
Mass of body m=500 g=0.5 kg
Distance, S=4 m
Initial velocity, u=0 ms1
Time taken, t=2 s.

Let force applied be F, acceleration be a and final velocity be v.

Applying, the second equation of motion, S=ut+12at2 and substituting the values we get,
4=0×2+12a×22
a=2 ms2.

From Newton's second law of motion ,
F=m×a=0.5×2=1 N.
Therefore, the force applied is 1 N.


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