Question

A body of mass $500g$ which is initially at rest is acted upon by a force. The body moves a distance of $4m$ in $2s$. The force applied is _____.

• A. $1N$
• B. $2N$
• C. $3N$
• D. $4N$

Answer 1

The correct option is A $1N$

Given,
Mass of body $m=500g=0.5kg$
Distance, $S=4m$
Initial velocity, $u=0m{s}^{-1}$
Time taken, $t=2s$.

Let force applied be $F$, acceleration be $a$ and final velocity be $v$.

Applying, the second equation of motion, $S=ut+\frac{1}{2}a{t}^2$ and substituting the values we get,
$4=0\times 2+\frac{1}{2}a\times 2^2$
$\Rightarrow$ $a=2m{s}^{-2}$.

From Newton's second law of motion ,
$F=m\times a=0.5\times 2=1N$.
Therefore, the force applied is $1N$.