a body of mass 500g tied to a string of length of 1m is revolved in the vertical circle with a constant speed.find the minimum speed at which there will not be any slack on the string?

Open in App

Solution

Dear student
$T e n s i o n i n t h e s t r i n g f o r a g i v e n s p e e d i s m i n i m u m a t t h e h i g h e s t p o s i t i o n o f v e r t i c a l c i r c u l a r p a t h . n e t c e n t r i p e t a l f o r c e T + m g = \frac{m v^{2}}{l} (T i s t e n s i o n i n s t r i n g l i s l e n g t h o f s t r i n g w h i c h i s e q u a l t o r a d i u s) m g = \frac{m v^{2}}{l} (f o r m i n i m u m s p e e d T = 0) g = \frac{v^{2}}{l} v = \sqrt{g l} = \sqrt{10 \times 1} = \sqrt{10} m / s R e g a r d s$

Suggest Corrections

Similar questions

Q. A particle of mass m is tied to a light string of length l and rotated along a vertical circular path. What should be the minimum speed at a highest point of its path so that the string does not become slack at any position?

Q. A body tied to a string of length

L

is revolved in a vertical circle with minimum velocity, when the body reaches the upper most point the string breaks and the body moves under the influence of the gravitational field of Earth along a parabolic path. The horizontal range

A C

of the body will be:

Q. A body is tied at the end of a string of length L and revolved in a vertical circle. The string is just taut when the body is at the highest position. Velocity of the body when the string is horizontal is

Q. A stone tied to string is rotated in a vertical circle. The minimum speed of the stone at the bottom most point so that it just completes the vertical circle.

A body of mass 1 kg tied to one end of string is revolved in a horizontal circle of radius 0.1 m with a speed of 3 revolution/sec, assuming the effect of gravity is negligible, then linear velocity, acceleration and tension in the string will be

Join BYJU'S Learning Program

a body of mass 500g tied to a string of length of 1m is revolved in the vertical circle with a constant speed.find the minimum speed at which there will not be any slack on the string?

Dear student Tension in the string for a given speed is minimum at the highest position of vertical circular path.net centripetal force T+mg=mv2l (T is tension in string l is length of string which is equal to radius)mg=mv2l (for minimum speed T=0)g=v2lv=gl=10×1=10m/sRegards