A body of mass 5kg is moving with a velocity of 10ms . a force is applied to it so that in 20s.attains a velocity of 35ms calculate the value of force applied

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Solution

$D e a r S t u d e n t, G i v e n, m = 5 k g, u = 10 m / s, t = 20 s, v = 35 m / s . A c c e l e r a t i o n, a = \frac{v - u}{t} = \frac{35 - 10}{20} = 1.25 m / s^{2} F = m a = 5 \times 1.25 = 6.25 N R e g a r d s . . .$

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A body of mass 5kg is moving with a velocity of 10ms . a force is applied to it so that in 20s.attains a velocity of 35ms calculate the value of force applied

Dear Student,Given,m = 5kg, u =10 m/s, t =20s, v=35 m/s.Acceleration , a=v-ut=35-1020=1.25m/s2F=ma=5×1.25=6.25NRegards...

$D e a r S t u d e n t, G i v e n, m = 5 k g, u = 10 m / s, t = 20 s, v = 35 m / s . A c c e l e r a t i o n, a = \frac{v - u}{t} = \frac{35 - 10}{20} = 1.25 m / s^{2} F = m a = 5 \times 1.25 = 6.25 N R e g a r d s . . .$