Question

A body of mass 5v Kg , is at rest on a table of coefficient of friction 0.1. If a force of 4N acts on a body then the acceleration of the body is:

• A. 5m$S^{-2}$
• B. 1/5m$S^{-2}$
• C. 1/2m$S^{-2}$
• D. zero

Answer 1

The correct option is D zero

Frictional force is a self-adjusting force and acts in the opposite direction of the imparted force.

f ≤ µN = 0.1*5*10

=> f ≤ 5

The force imparted to the body is 4N which is less than the maximum frictional force. Hence f = 4 N

Net force on the body,

=> F – f = 4 – 4 = 0.

Thus, acceleration, a = zero