You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Second Law of Motion

A body of mas...

Question

A body of mass $6 k g$ is hanging from another body of mass $10 k g$ as shown in figure. This combination is being pulled up by a string with an acceleration of $2 m s^{- 2}$ , the tension $T_{1}$ is $(g = 10 m s^{- 2})$ .

240 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

150 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

220 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

192 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $240 N$
$\begin{matrix} T_{1} = (M_{1} + M_{2}) a + (M_{1} + M_{2}) g T_{1} = (12 + 8) (2) + (12 + 8) (10) T_{1} = (20) (2) + (20) (10) T_{1} = 40 + 200 T_{1} = 240 N \end{matrix}$
Hence,
option $(A)$ is correct answer.

Suggest Corrections

Similar questions

Q. A body of mass

8 k g

is hanging from another body of mass

12 k g

.The combination is being pulled up by a string with an acceleration of

2.2 m / {s e c}^{2}

. The tension

T_{1}

will be

A body of mass 10kg is hanging from another body of mass 15kg. The combination is pulled up by a string with an acceleration of . $1.2 m^{- 2}$ Find the tensions (in N) at A and B points as shown in figure $(T a k e g = 9.8 m / s^{2})$ .

Q. A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled by a string with an acceleration of 2.2 m

s^{- 2}

. The tension

T_{1}

and

T_{2}

will be respectively : (use g = 9.8

m / s^{2}

)

Q. In the figure shown, the

12 k g

body pulled by a string with an acceleration

a = 2.2 m / s^{2}

. The tension

T_{1}

and

T_{2}

will be respectively
(Take

g = 9.8 m / s^{2}

)

Join BYJU'S Learning Program

A body of mass 6 kg is hanging from another body of mass 10 kg as shown in figure. This combination is being pulled up by a string with an acceleration of 2 ms−2, the tension T1 is (g=10ms−2).

The correct option is A 240 NT1=(M1+M2)a+(M1+M2)gT1=(12+8)(2)+(12+8)(10)T1=(20)(2)+(20)(10)T1=40+200T1=240NHence,option (A) is correct answer.

A body of mass $6 k g$ is hanging from another body of mass $10 k g$ as shown in figure. This combination is being pulled up by a string with an acceleration of $2 m s^{- 2}$ , the tension $T_{1}$ is $(g = 10 m s^{- 2})$ .

The correct option is A $240 N$
$\begin{matrix} T_{1} = (M_{1} + M_{2}) a + (M_{1} + M_{2}) g T_{1} = (12 + 8) (2) + (12 + 8) (10) T_{1} = (20) (2) + (20) (10) T_{1} = 40 + 200 T_{1} = 240 N \end{matrix}$
Hence,
option $(A)$ is correct answer.