A body of mass $70 k g w t$ , when completely immersed in water, displaces $20, 000 c m^{3}$ of water. Find the mass of body in water.

70 k g w t

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50 k g w t

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20 k g w t

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90 k g w t

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Solution

The correct option is B $50 k g w t$
We know $1 m^{3} = 1000000 c m^{3}$

$⟹$ $V = 20000 c m^{3} = 0.02 m^{3}$

So Buoyancy force $F = V ρ g = 0.02 \times 1000 \times 10 = 200 N$

Mass of body in air $m g = 70 k g$

So net weight of body in water $W = m g - F = 70 \times 10 - 200 = 500 N$

So mass of body in water $m_{w} = \frac{500}{10} = 50 k g w t$

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A body of mass 70kgwt, when completely immersed in water, displaces 20,000cm3 of water. Find the mass of body in water.

The correct option is B 50kgwtWe know 1m3=1000000 cm3⟹ V=20000 cm3=0.02m3So Buoyancy force F=Vρg=0.02×1000×10=200 NMass of body in air mg=70 kgSo net weight of body in water W=mg−F=70×10−200=500NSo mass of body in water mw=50010=50 kgwt

A body of mass $70 k g w t$ , when completely immersed in water, displaces $20, 000 c m^{3}$ of water. Find the mass of body in water.