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Second Law of Motion

A body of mas...

Question

A body of mass $\frac{1}{4}$ kg moving with velocity 12m/s is stopped by applying a force of 0.6N. Calculate the time taken to stop the body. Also calculate the impulse of this force.

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Solution

Acceleration provided by force.
$a = \frac{0.6}{\frac{1}{4}}$
$a = 2.4 m s^{- 2}$
$v = u + a t$
$0 = 12 - 2.4 t$
$t = 5$ sec
Impulse=Force $\times$ Time
Impulse= $0.6 \times 5$
$⟹ 3 N - s$

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