A body of mass J kg is moving with velocity of 10 $m s^{- 1}$ .After force is applied to it so that in 25 sec it attains a velocity of 35 m $s^{- 1}$ . Calculate the value of force applied.

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Solution

We have,

$m a s s = j k g$

$u = 10 m / s, v = 35 m / s$

$t = 25 s$

Since we know that,

$f = m a = m \times \frac{v - u}{t}$

$= \frac{35 - 10}{25} (J) = J$

Thus, the value of force applied is $= J N$

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A body of mass J kg is moving with velocity of 10 ms−1.After force is applied to it so that in 25 sec it attains a velocity of 35 ms−1. Calculate the value of force applied.

We have,mass=jkgu=10m/s,v=35m/st=25sSince we know that, f=ma=m×v−ut=35−1025(J)=JThus, the value of force applied is =JN

A body of mass J kg is moving with velocity of 10 $m s^{- 1}$ .After force is applied to it so that in 25 sec it attains a velocity of 35 m $s^{- 1}$ . Calculate the value of force applied.

We have,

$m a s s = j k g$

$u = 10 m / s, v = 35 m / s$

$t = 25 s$

Since we know that,

$f = m a = m \times \frac{v - u}{t}$

$= \frac{35 - 10}{25} (J) = J$

Thus, the value of force applied is $= J N$