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Acceleration

A body of mas...

Question

A body of mass $m_{1}$ collides elastically with a stationary body of mass $m_{2}$ and returns along the same line with one fourth of its initial speed, then $m_{1} / m_{2} =$

1

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2

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0.60

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0.33

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Solution

The correct option is C $0.60$

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\begin{matrix} Column - I & Column -II (a) After the collision, velocity of second & (p) > 1 body is maximum when \frac{m_{1}}{m_{2}} is (b) After the collision, the momentum & (q) < 1 of second body is maximum when \frac{m_{1}}{m_{2}} is (c) After the collision, K.E. of second & (r) = 1 body is maximum when \frac{m_{1}}{m_{2}} is (D) For elastic collision, coefficient of & (s) = 0 restitution is \end{matrix}

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