A body of mass $m_{1}$ is moving with a velocity 'v'. It collides with another stationary body of mass $m_{2}$ . They get embedded. At the point of collision, the velocity of the system is

Increases

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Decreases but does not become zero

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Remains same

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Become zero

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Solution

The correct option is
D

Decreases but does not become zero

By momentum conservation before and after collision.

$m_{1} V + m_{2} \times 0 = (m_{1} + m_{2}) v \Rightarrow v = \frac{m_{1}}{m_{1} + m_{2}} V$ i.e.

Velocity of system is less than 'V' .

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A body of mass m1 is moving with a velocity 'v'. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system is

The correct option is D Decreases but does not become zeroBy momentum conservation before and after collision. m1V+m2×0=(m1+m2)v⇒v=m1m1+m2V i.e. Velocity of system is less than 'V' .

A body of mass $m_{1}$ is moving with a velocity 'v'. It collides with another stationary body of mass $m_{2}$ . They get embedded. At the point of collision, the velocity of the system is

The correct option is
D

Decreases but does not become zero

By momentum conservation before and after collision.

$m_{1} V + m_{2} \times 0 = (m_{1} + m_{2}) v \Rightarrow v = \frac{m_{1}}{m_{1} + m_{2}} V$ i.e.

Velocity of system is less than 'V' .