A body of mass $m_{1}$ , is moving with a velocity V. it collides with another stationery body of mass $m_{2}$ , they get embedded. At the point of collision , the velocity of the system

Increases

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Decreases but does not become zero

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Remains same

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Become zero

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Solution

The correct option is B Decreases but does not become zero
Just before the collision the velocity of the $c e n t e r$ of mass will be $u = \frac{m_{1} \times V + m_{2} \times 0}{m_{1} + m_{2}} = \frac{m_{1}}{m_{1} + m_{2}} V$

after the collision if the system moves with velocity $V_{0}$ then on conserving the momentum
we will get $m_{1} V + 0 = (m_{1} + m_{2}) V_{0}$

or $V_{0} = \frac{m_{1}}{m_{1} + m - 2} V$

we can notice that both $V_{0}$ and $u$ are same, due to absence of external force on the $s y s t e m .$

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A body of mass m1, is moving with a velocity V. it collides with another stationery body of mass m2, they get embedded. At the point of collision , the velocity of the system

A body of mass $m_{1}$ , is moving with a velocity V. it collides with another stationery body of mass $m_{2}$ , they get embedded. At the point of collision , the velocity of the system