A body of mass m=5kg is thrown at an angle θ=30∘ to the horizontal with the initial velocity v0=20m/s. Assuming the air drag to be negligible, find the magnitude of the momentum increment Δp during the total time of motion.
A
0kg m/s
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B
50kg m/s
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C
100kg m/s
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D
10kg m/s
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Solution
The correct option is C100kg m/s As we know that, →Fext=d→pdt Here, →Fext=−(mg)^j= constant ⇒F=dpdt=ΔpΔt (if F is constant) at t=0 Here, mg=ΔpΔt⇒Δp=mg(Δt) where, Δt is the Time of flight or Δp=mg2V0sinθg Or, Δp=2mv0sinθ=2mv0sin30∘ Or, Δp=mv0=5×20=100kg m/s