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Question

A body of mass m=5 kg is thrown at an angle θ=30 to the horizontal with the initial velocity v0=20 m/s. Assuming the air drag to be negligible, find the magnitude of the momentum increment Δp during the total time of motion.


A
0 kg m/s
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B
50 kg m/s
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C
100 kg m/s
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D
10 kg m/s
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Solution

The correct option is C 100 kg m/s
As we know that,
Fext=dpdt
Here, Fext=(mg)^j= constant
F=dpdt=ΔpΔt (if F is constant) at t=0
Here, mg=ΔpΔtΔp=mg(Δt) where, Δt is the Time of flight
or Δp=mg2V0sinθg
Or, Δp=2mv0sinθ=2mv0sin30
Or, Δp=mv0=5×20=100 kg m/s

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