Question

A body of mass m accelerates uniformly from rest to velocity $v_1$ in time interval $T_1$. The instantaneous power delivered to the body as a function of time t is

• A. $\frac{m{v}_1^2}{T_1^2}t$
• B. $\frac{m{v}_1}{T_1^2}t$
• C. ${\left(\frac{m{v}_1}{T_1}\right)}^{2}t$
• D. $\frac{m{v}_1^2}{T_1}{t}^2$

Answer 1

The correct option is A $\frac{m{v}_1^2}{T_1^2}t$

$a=\frac{V_1}{T_1}\therefore v=u+at=0+\left(\frac{V_1}{T_1}\right).tP=FV=mav=m\left(\frac{V_1}{T_1}\right).\left(\frac{V_1}{T_1}\right).t=m{\left(\frac{V_1}{T_1}\right)}^2.t$