A body of mass M and charge q is suspended from a string. When slightly displaced, it oscillates with period T. If a uniform electric field acts vertically downwards, then the new time period will be:
A
T′=T
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B
T′<T
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C
T′>T
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D
cannot be predicted
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Solution
The correct option is BT′<T Here, T=2π√lg When electric field is applied downward the effective acceleration will increase i,e g′=g+qEM Thus, T′=2π√lg+qE/M Hence, T′<T